Find zeroes of polynomial 9x²-4
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Answer:
x = 2/3 and -2/3
Step-by-step explanation:
==: 9x² - 4 = 0
==: (3x)² - (2)² = 0 [a² - b² = (a+b) (a-b)]
==: (3x - 2) (3x + 2) = 0
==: x = 2/3 and -2/3
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