Math, asked by Rishi3234, 9 months ago

find zeroes of polynomial for
1. x square - x- 12
2. x square - 6x +9
3. x square - 4x5
4. x square + 3x - 4
5. x square - 1​

Answers

Answered by Anonymous
3

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1.

 {x}^{2}  - x - 12 \\  {x}^{2}  - 4x + 3x - 12 \\ x(x - 4) + 3(x - 4) \\ (x - 4)(x + 3) \\

so the zeros of this polynomial are

x = 4 \: and \: x =  - 3

2.

 {x}^{2}  - 6x + 9 \\  {x}^{2} - 3x - 3x + 9 \\ x(x - 3) - 3(x - 3) \\ (x - 3)(x - 3)

so the zeros of this polynomial are

x=3

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