Question

find zeroes of polynomial p(x)= x2 - 14
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Answer 1

Answer:

$x=+\sqrt{14} , -\sqrt{14}$

Step-by-step explanation:

$x^{2} -14=0\\x^{2} =14\\\sqrt{x^{2} } = \sqrt{14} \\x=+\sqrt{14},-\sqrt{14}$