Find zeroes of polynomial: p(x) = x²/3 - 4x + 7/3
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Step-by-step explanation:
p(x) = x²/3 - 4x + 7/3
multiply the whole equation with '3'
0×3=(x²/3-4x+7/3)3
0=x²-12x+7
a=1,b= -12,c=7
by quadratic formula= -b±√b²-4ac/2a
= -(-12)±√(-12)²-4(1)(7)/2(1)
=12±√144-28/2
=12±√116/2
=12±2√29/2
=2(6±√29)/2
=(6±√29)
roots are 6+√29 or 6-√29
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