Question

Find zeroes of polynomial


$x {}^{2} - \: 4$

Answer 1

HOLA

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$x {}^{2} \: - \: 4 \: = \: ( \: x \: + \: \sqrt{4} ) \: ( \: x \: - \: \sqrt{4} ) \\ \\ \\ x \: = \: \sqrt{4} \\ \\ x \: = \: - \: \sqrt{4}$

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HOPE U UNDERSTAND ❤❤❤

Answer 2

Let f(x) = x^2 - 4.

Zeroes of the polynomial is f(x) = 0

= > x^2 - 2^2 = 0

We know that a^2 - b^2 = (a + b)(a - b)

= > (x + 2)(x - 2) = 0

= > x = -2,2.

Therefore, the zeroes of the polynomial is 2,-2.

Hope this helps!