Math, asked by ayantanwar123, 1 year ago

find zeroes of polynomial x^2-x-72 and verify relation between the zeroes and co-coeficients


ill give brainliest please answer​

Answers

Answered by ankitrk72
0

Step-by-step explanation:

x²-x-72

x²-9x+8x-72

x(x-9)+8(x-9)

(x-9)(x+8)

Answered by tharuntge
2

Step-by-step explanation:

x^2-x-72=0

x^2-9x+8x-72=9

x(x-9)+8(x-9)=0

(x+8)(x-9)=0

x=-8&x=9.

a=1,b=-1,c=-72

€......be the alpha

¢......be the bita

(£+¢)=-b/a

(-8+9)=-(-1/1)

1=1

£¢=c/s

(-8×9)=-72/1

-72=-72

Hence relation between the zeros and co-efficient is verified.

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