find zeroes of polynomial x^2-x-72 and verify relation between the zeroes and co-coeficients
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Answers
Answered by
0
Step-by-step explanation:
x²-x-72
x²-9x+8x-72
x(x-9)+8(x-9)
(x-9)(x+8)
Answered by
2
Step-by-step explanation:
x^2-x-72=0
x^2-9x+8x-72=9
x(x-9)+8(x-9)=0
(x+8)(x-9)=0
x=-8&x=9.
a=1,b=-1,c=-72
€......be the alpha
¢......be the bita
(£+¢)=-b/a
(-8+9)=-(-1/1)
1=1
£¢=c/s
(-8×9)=-72/1
-72=-72
Hence relation between the zeros and co-efficient is verified.
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