Question

find zeroes of polynomial x2-3 and verify the relation between the zeroes and the coefficients​

Answer 1

Answer:

+root 3, - root 3

Step-by-step explanation:

x²=3

x=+ or - root 3

x=+ root3,- root 3

sum of zeroes= root 3- root 3=0=-b/a

product of zeroes=(root3)(-root3)=-3=c/a

Answer 2

Answer:

x²-3 = 0

x² = 3

x = ±√3

Therefore, the zeroes of the given polynomial are √3 and -√3.

Relationship between the zeroes and coefficients :-

Sum of zeroes = √3+(-√3) = √3-√3

= 0 = -x coefficient/x² coefficient

Product of zeroes = (√3)(-√3)

= -(√3)² = -3/1 = constant/x² coefficient

Hope it helps

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