find zeroes of polynomial x2 + 4x -192
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Answered by
1
X+1=0
X=-1
X2+4x-192
1+4-192
5-192
-187
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X=-1
X2+4x-192
1+4-192
5-192
-187
Please follow me and make me brainilist
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Answered by
10
Your answer
x2 + 4x - 192
By middle term spilt
x2 + (16x - 12 x) - 192
x2 + 16x - 12x - 192
x(x+16)-12(x+16)
(x+16)(x-12)
For zeroes
x+16=0 or x-12=0
x=-16 or x=12
x2 + 4x - 192
By middle term spilt
x2 + (16x - 12 x) - 192
x2 + 16x - 12x - 192
x(x+16)-12(x+16)
(x+16)(x-12)
For zeroes
x+16=0 or x-12=0
x=-16 or x=12
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