Question

find zeroes of polynomial x2-(root3 +1)x+root3

Answer 1

Hola Mate !!

Here's your answer :-

${x}^{2} - ( \sqrt{3} + 1)x + \sqrt{3} \\ = > {x}^{2} - \sqrt{3} x - x + \sqrt{3} \\ = > x(x - \sqrt{3} ) - 1(x - \sqrt{3} ) \\ = > (x - \sqrt{3} )(x - 1)$

Hope it helps
Mark me as brainliest if it's correct.

Answer 2

=x2-(√3+1)X+√3 =x2-√3x-x+√3 =X(x-√3)-1(x-√3) =(x-√3)(x-1)   When= x-√3=0. And when = x-1=0                X =√3 and.            X=1 Hence zeros are √3 and 1