Find zeroes of polynomial x2-x-12 andcheck relation between coefficients and zeroes
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Answer:
Step-by-step explanation:
X²-x-12
12x²:- 4x*3x=12x²
4x-3x=1x
So,
X²-4x+3x-12
1x(x-4)+3(x-4)
(X-4) (x+3)
The zeroes are -3,4
Sum of 0's= -3+4=-1
Product of 0's= -3*4= -12
Sum of coefficients= -b/a = -1/1= -1
Product of coefficients= c/a= -12/1 = -12
Therefore, the sum and product of both zeroes and coefficients are equal.
Hope the answer helps u
shagufta028:
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