Question

find zeroes of quadratic polynomial -12+t+6t²
please​

Answer 1

Answer:

$6 {t}^{2} + t \: - 12$

$6 {t}^{2} \: + 9t \: - 8t \: - 12$

$3t \: (2t \: + \: 3) - 4(2t \: + 3 \: )$

$3t \: - 4 = 0$

And

$2t \: + 3 = 0$

Now

$3t \: - 4 = 0$

$3t \: = 4$

$t \: = \frac{4}{3}$

And

$2t \: + 3 = 0$

$2t \: = - 3$

$t \: = \frac{ - 3}{2}$

Ans) the value of t is 4/3 and - 3/2.