find zeroes of quadratic polynomial 3x2+11x-4
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Hey"
Here is your answer.
3x2+11x-4
a=3,b=11 and c=-4
D=b2-4ac
D=(11)2 -4*3*-4
D=121+48
D=169
alpha= -b -underoot D/2a Beta= -b+underootD/2a
= -11-underoot169/2*3 = -11+underoot169/6
=-11-13/6 = -11 + 13/6
= -4 = 1/3
Hope it is helpful to you.
Here is your answer.
3x2+11x-4
a=3,b=11 and c=-4
D=b2-4ac
D=(11)2 -4*3*-4
D=121+48
D=169
alpha= -b -underoot D/2a Beta= -b+underootD/2a
= -11-underoot169/2*3 = -11+underoot169/6
=-11-13/6 = -11 + 13/6
= -4 = 1/3
Hope it is helpful to you.
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