Question

find zeroes of quadriatic polynomial a) n2-2n-8 b) 3n2-n-4

Answer 1

(a) n²-2n-8

n²-4n+2n-8

n(n-4)+2(n-4)

(n-4)(n+2)

zero of the polynomial

n-4=0. n+2=0

n=4. n=-2

(b)3n²-n-4

3n²+3n-4n-4

3n(n+1)-4(n+1)

(3n-4)(n+1)

zero of the polynomial

3n-4=0. n+1=0

n=4/3. n=-1