Question

Find zeroes of route3x^2-8x+4root3

Answer 1

Answer:

Given quadratic equation = √3x² - 8x + 4√3 = 0

We should factorize the equation first.

          =√3x²-6x-2x+4√3 = 0

          = √3x(x-2√3)-2(x-2√3) = 0 

          = (√3x-2) (x-2√3) = 0

          = (√3x-2) = 0 , (x-2√3) = 0

          = x = 2/√3 or, x = 2√3.