Math, asked by kg1223422, 9 months ago

find zeroes of
100x { }^{2} - 81 \: find \: zeroes

Answers

Answered by Pragya3918red
2

Step-by-step explanation:

100x² - 81

= (10x)² - (9)²

= (10x + 9)(10x - 9)

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Answered by Anonymous
1

HeYa❤️...

Answer:

Identity Used:

(x) {}^{2}  + (y) {}^{2}  = (x + y)(x - y)

Solution:

  100x {}^{2}  - 81 = 0 \\  \\ (10x) {}^{2}   - (9) {}^{2}  = 0 \\  \\ (10x + 9)(10x - 9) = 0 \\  \\ x =  \frac{ - 9}{10}  \: or \:   + \frac{9}{10}

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