Question

Find zeroes of the following quadratic polynomial p(x) =x^2+43x+222

Answer 1

$<h2> hey DUDE </h2>$
given :- p(x) = x² + 43x + 222

by splitting method we get,

→ x² + (37x + 6x) + 222 = 0

→ x² + 37x + 6x + 222 = 0

→ x(x + 37) + 6(x + 37) = 0

→ (x + 37) (x + 6) = 0

therefore x is -37 or -6 ( x + 37 = 0 => x = -37, x + 6 = 0 => x = -6)

Answer 2

$hey \: mate \: here \: is \: ur \: answer \\ given \: \\ {x}^{2} + 43x + 222 = 0 \\ {x}^{2} + 37x + 6x + 222 = 0 \\ x(x + 37) + 6(x + 37) = 0 \\ (x + 37)(x + 6) = 0 \\ therefore \: \\ zeroes \: of \: the \: equation \: are \\ \: - 6 \: and \: - 37 \\ plzzz \: mark \: as \: brainliest$