find zeroes of the polynomial 3x²-x-4
Answers
Answered by
8
Answer:
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Step-by-step explanation:
3x^-x-4=0
3x^-4x+3x-4=0
3x^+3x-4x-4=0
3x(x+1)-4(x+1)=0
(3x-4)(x+1)=0
3x-4=0 3x=4 x=4/3
x+1=0 x=-1
Answered by
4
Answer:
The zeroes are -1 and 4/3
Step-by-step explanation:
Given p(x) : 3x^2 - x -4
To find : Zeroes of p(x)
Solution : Splitting the middle term
=3x^2 - x - 4
= 3x^2 - 4x +3x - 4
= x(3x - 4) + 1(3x - 4)
=(x+1)(3x-4)
Therefore, (x+1) & (3x-4) are equal to zero when
x= -1
x= 4/3
Therefore zeroes of polynomial is -1 & 4/3
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