Question

find zeroes of the polynomial 49Xsquare-9​

Answer 1

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Answer 2

Answer:

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Explanation:Answer:

$Given \ p(x)=49x^{2}-9\\\\using \ identity \ a^{2}- b^{2}=(a-b)(a+b) \\\\p(x)=(7x)^{2}-(3)^{2}\\\\p(x)=(7x+3)(7x-3)\\\\(7x+3)=0 \ or \ (7x-3)=0\\\\x=\frac{-3}{7} \ or \ x=\frac{3}{7}\\\\\\So \ \frac{3}{7} \ and \ \frac{-3}{7} \ are zeroes \ of \ 49x^{2} -9$

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