Question

find zeroes of the polynomial=4x^2-1​

Answer 1

Answer:

1/2 , -1/2

Step-by-step explanation:

4x^2-1

(2x)^2 - (1)^2

using the identity a^2 - b^2 = ( a+b ) ( a-b)

( 2x + 1 ) ( 2x - 1 )

x = -1/2 , 1/2 are the zeros of polynomial 4x^2 - 1

Hope this will help

Answer 2

Step-by-step explanation:

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