Question

find zeroes of the polynomial 5√5y²+30y+8√5

Answer 1

Answer:

y = -2/√5 & y = -4/√5

Step-by-step explanation:

given polynomial is 5√5y² + 30y + 8√5

we have to find the zeroes of that polynomial,

so, 5√5y² + 30y + 8√5 = 0

=> 5√5y² + 20y + 10y + 8√5 = 0

=> 5y(√5y + 4) + 2√5(√5√y + 4) = 0

=> (5y + 2√5)(√5y + 4) = 0

=> (5y + 2√5) = 0 , (√5y + 4) = 0

=> y = -2√5/5 & y = -4\√5

=> y = -2/√5 & y = -4/√5

thanks,

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