Question

find zeroes of the polynomial y3-7y+6

Answer 1

y³ - 7y + 6 = 0

Put y = 1

It satisifies it.

So, y - 1 is a factor

Divide the polynomial by y - 1

We get y² + y - 6 = 0

So, y = 2 , -3

So, the roots are 1,2 and -3