Find zeroes of the quadratic polynomial 2√3x²-5x+3
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Answer:
Solve by splitting middle term
=> 2√3x² - 5x - √3 = 0
=> 2√3x² - 6x + x - √3 = 0
=> 2√3x (x - √3) + 1 (x - √3) = 0
=> (x - √3) (2√3x + 1) = 0
Either
=> x - √3 = 0
=> x = √3
or
=> 2√3x + 1 = 0
=> 2√3x = -1
=> x = -1/2√3
√3 and -1/2√3 are the zeros
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