Question

Find zeroes of the quadratic polynomials 4s2-4s+1

Answer 1

Answer:

$\\ \tt \: 4 {s}^{2} - 2s - 2s + 1 \\ \\ \\ \implies \tt \: 2s \: (2s - 1) \: - 1 \: (2s - 1) \\ \\ \\ \implies \tt \blue{(2s - 1) \: (2s - 1)}$

So, zeroes are 1/2 and 1/2 .

$\\ \tt \implies \: 2s - 1 = 0 \\ \\ \\ \tt \implies \: 2s = 1 \\ \\ \\ \tt \implies \: s = \frac{1}{2}$

or,

$\\ \\ \tt \: 2s - 1 = 0 \\ \\ \implies \tt \: x = \frac{1}{2}$