Find zeroes of the quadratic polynomialx2 + 4x + 3 , and verify the relationship between the zeroes and the coefficients.
Answers
Step-by-step explanation:
The given quadratic polynomial is,
p(x) =4x² - 4x - 3
=> 4x² - 6x + 2x - 3
=> 2x( 2x -3) + 1(2x + 3)
=> (2x + 1) (2x -3)
p(x) = 0
(2x + 1) = 0 or (2x-3) = 0
x=-1/2 or x= 3/2
Hence, -1/2 and 3/2 are the zeroes of p(x).
Sum of zeroes = -1/2 + 3/2 = 2/2 = 1 = Coefficient of x / Coefficient of x²
Product of zeroes = (-1/2)(3/2) = -3/4 = Constant term/ Coefficient of x²
Answer:
Hey mate. Your answer is.....
Step-by-step explanation:
The given quadratic polynomial is,
p(x) =4x² - 4x - 3
=> 4x² - 6x + 2x - 3
=> 2x( 2x -3) + 1(2x + 3)
=> (2x + 1) (2x -3)
p(x) = 0
(2x + 1) = 0 or (2x-3) = 0
x=-1/2 or x= 3/2
Hence, -1/2 and 3/2 are the zeroes of p(x).
Sum of zeroes = -1/2 + 3/2 = 2/2 = 1 = Coefficient of x / Coefficient of x²
Product of zeroes = (-1/2)(3/2) = -3/4 = Constant term/ Coefficient of x².
Hope it helps! :)