Math, asked by gangarajut36, 1 month ago

find zeroes of x^2+2x-8

Answers

Answered by panchanansharma58

3

Answer:

see steps

Step-by-step explanation:

x^2 + 2x - 8

x^2 + 4x - 2x - 8

x(x + 4) -2(x + 4)

(x + 4) (x - 2)

x + 4 = 0

x = -4

x - 2 = 0

x = 2

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