Question

find zeroes of x^2-4 and also verify relationship with coefficients of terms of polynomial​

Answer 1

Answer:

zeroes are -2 and 2

Step-by-step explanation:

x² - 4 = 0

x² = 4

taking square root on both side

x = ±2

x = -2 , +2

verification

sum of zeroes = -b/a

-2 + 2 = -0/1

0 = 0

product of zeroes = c/a

-2 × 2 = -4/1

-4 = 4

Answer 2

let the zeros of this polynomial be â and ã

zero of the polynomial x^2 - 4 => x^2 - 4 = 0

=> x^2 = 4

=> x = ±2

therefore zeros are ±2

as per relationship of cooeficients of terms of polynomial

â × ã = c/a

and â + ã =-b/a

here +2×-2= -4 = c/a =-4/1=-4

and +2 + -2 =0 = -b/a = -0/1 = 0

because here a is 1 b is 0 and c is -4

thank u