find zeroes of x cube plus 4x square plus x minus 6
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Step-by-step explanation:
x³+4x²+x-6
a = 1, b = 4, c = 1, d = -6
→ Sum of zeroes = -b/a = -4
→ Sum of the product of zeroes taken two at a time = c/a = 1
→ Product of zeroes = -d/a = -(-6)/1 = 6
Hope this will be helpful to you.
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