find zeroes of x2-2x-80
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Answered by
1
x2-2x-80
x2-10x+8x-80
x(x-10)+8(x-10)
(x-10)(x+8)
x=10
x=-8
x2-10x+8x-80
x(x-10)+8(x-10)
(x-10)(x+8)
x=10
x=-8
Answered by
7
Heya..
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To find zeroes,
Firstly factorise it.
= x^2 - 2x - 80
= x^2 - 10x + 8x - 80
= x(x-10) + 8(x-10)
= (x+8) (x-10)
Hence (x+8) = 0 and
(x-10) = 0....
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Hence x = - 8 and x = 10.
Zeroes are - 8 and 10.
Hope it's helpful to u.
--------------------
To find zeroes,
Firstly factorise it.
= x^2 - 2x - 80
= x^2 - 10x + 8x - 80
= x(x-10) + 8(x-10)
= (x+8) (x-10)
Hence (x+8) = 0 and
(x-10) = 0....
--------------
Hence x = - 8 and x = 10.
Zeroes are - 8 and 10.
Hope it's helpful to u.
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