Question

find zeroes with steps
3x²+4x-4

Answer 1

3x^2+4x-4=0

3x^2+6x-2x-4=0

3x(x+2)-2(x+2)=0

(3x-2)(x+2)=0

x=2/3,-2

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Answer 2

Step-by-step explanation:

$3x {}^{2} + 4x - 4 \\ = 3x {}^{2} + 6x - 2x - 4 \\ = 3x(x + 2) - 2(x + 2) \\ = (3x - 2)(x + 2)$

hence zeroes are 2/3 or -2