find zeroes, y intercept and vertex of quadratic expression y= 2x²+5x+2
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Answer:
y=2x^2+(4+1)x+2
y =2x^2 +4x + 1x + 2
y=2x(x+2) 1(x+2)
y= (x+2) (2x+1)
so x= - 2 and -1/2
now put value of x and find y
hope it helps
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