Question

find zerores of polynomial p(x)=x2-2x-8​

Answer 1

Answer:

Step-by-step explanation:

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Answer 2

$\large{ {x}^{2} - 2x - 8 }$

$\large{ {x}^{2} - 4x + 2x - 8}$

$\large{x(x - 4) + 2(x - 4)}$

$\large \bold{ \: (x - 4)(x + 2) \: }$

$\huge\blue\ \ \: {thanks}$