Question

find zeros 2x square -x-45​

Answer 1

Step-by-step explanation:

$\huge\underline{\underline{\sf ANSWER}} \\ \huge \: hey.....$

$2 {x}^{2} - x - 45 = 0 \\ \\ a = 2 \\ b = -1 \\ c = -45 \\ \\ x = \frac{ - b + \: or - \sqrt{ {b}^{2} - 4ac} }{2a} \\ x = \frac{1 + \: or \: - \sqrt{361} }{4} \\ x = \frac{1 + 19}{4} \: \: \: \: or \: \: \: \: x = \frac{1 - 19}{4} \\ x = 5 \: \: \: \: \: \: \: \: \: \: \: \: \: \: or \: \: \: \: \: x = \frac{ - 9}{2}$

Answer 2

Answer:

$2 {x}^{2} - x - 45 \\ \\ a = 2 \\ b = - 1 \\ c = - 45 \\ \\ x = \frac{ - b - \sqrt{ {b}^{2} - 4ac } }{2a} \\ \\ = \frac{ - ( - 1) \sqrt{ {( - 1)}^{2} - 4 \times 2 \times ( - 45)} }{2 \times 2} \\ \\ = \frac{1 \sqrt{1 + 360} }{4} \\ \\ = \frac{1 \sqrt{361} }{4} \\ \\ = \frac{1 + - 19}{4} \\ \\ taking \: + \\ x = \frac{1 + 19}{4} \\ \\ x = \frac{20}{4} \\ \\ x = 5 \\ \\ taking \: - \\ \\ x = \frac{1 - 19}{4} \\ \\ x = \frac{ - 18}{4} \\ \\ x = \frac{ - 9}{2}$