Find zeros and verity relationship between zeros and
the coufficient of x²-2x-8.
please answer. if you answer I give you a brainlist answer. please answer because my collage exam is going
Answers
Answered by
2
Step-by-step explanation:
let f(x) = x2 - 2x - 8
=> x2 - 4x + 2x - 8
=> x(x - 4) + 2(x - 4)
=> (x - 4) (x + 2)
to find the zeroes... set f(x) = 0,
then either (x ˗ 4) = 0 or (x+2) = 0 x = 4 or x = -2
Again, Sum of zeroes = (4 – 2) = 2 = 2/1 = -b/a = (-Coefficient of x)/(Coefficient of x2)
Product of zeroes = (4) (-2) = -8/1 = c/a = Constant term / Coefficient of x2
Answered by
1
Answer:
0 of the polynomial is 4..
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