Question

find zeros by factorization x^2-6x+8​

Answer 1

Step-by-step explanation:

x^2 -4x -2x +8

x{x-4} -2{x-4}

{x-2} {x-4}

Answer 2

${x}^{2} - 6x + 8$

Let p(x) = x^2 - 6x + 8

Zero of the polynomial is the value of x where p(x) = 0.

putting p(x) = 0

${x}^{2} - 6x + 8 = 0$

We find roots using splitting the middle term method

x^2 - 6x +8

x^2 - 4x - 2x + 8

x( x-4) - 2 ( x - 4)

(x -4)(x -2).

So, x = 4, 2.

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