Find Zeros by Quadratic formula:: 2x^2-89x+210
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Answer:
5/2 and 42
Step-by-step explanation:
ax² + bx + c = 0
= ( - b ± √D ) / 2a
D = b² - 4ac
~~~~~~~~~
f(x) = 2x² - 89x + 210
2x² - 89x + 210 = 0
D = (- 89)² - 4(2)(210) = 6241 = 79²
= (89 - 79) / 4 = 5/2
= (89 + 79) / 4 = 42
Zeros of f(x) are 5/2 and 42
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