Question

Find Zeros by Quadratic formula:: 2x^2-89x+210

No Spam
Otherwise I will report it..​

Answer 1

Answer:

5/2 and 42

Step-by-step explanation:

ax² + bx + c = 0

$x_{12}$ = ( - b ± √D ) / 2a

D = b² - 4ac

~~~~~~~~~

f(x) = 2x² - 89x + 210

2x² - 89x + 210 = 0

D = (- 89)² - 4(2)(210) = 6241 = 79²

$x_{1}$ = (89 - 79) / 4 = 5/2

$x_{2}$ = (89 + 79) / 4 = 42

Zeros of f(x) are 5/2 and 42