Question

Find Zeros (es) of the polynomial in each of the following case (i) x^2+7x+10

Answer 1

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${x}^{2} + 7x + 10 = 0 \\ {x}^{2} + 5x + 2x + 10 = 0 \\ x(x + 5) + 2(x + 5) = 0 \\ (x + 2)(x + 5) = 0 \\ x = - 2 \\ x = - 5$

Zeros are -2 and -5

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Answer 2

x2+7x+10=0

x2+2x+5x+10=0

x (x+2)5 (x+2)=0

(x+2)(x+5)=0

x+2=0, x+5=0

x=-2, x=-5

zeroes are -2 , -5

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