Question

find zeros of 3x square -5x-4 and verify the relation between zeroes and its coefficients​

Answer 1

Answer:

5 +√29 5 -√29

x = ----------- , x = -----------

6 6

Step-by-step explanation:

3x^2-5x-4 = 0

On comparing given equation with ax^2+bx+c = 0,

we get: a=3

b=(-5)

c=(-4)

For real roots,

Discriminant (D) ≥ 0

(b^2-4ac) ≥ 0

[(-5)^2 - 4×3×(-4)] ≥ 0

(25+24) ≥ 0

29 ≥ 0

D = 29

-b ±√D 5 ±√29

x = ----------- =} ----------------

2a 6

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