Question

Find zeros of 4 root 3x square + 5x -2 root 3

Answer 1

4√3 x² +5x -2√3 =0
⇒4√3 x² +8x -3x -2√3=0
⇒4x(√3 x+2) -√3(√3x +2) =0
⇒(√3x +2)(4x -√3) =0
⇒(√3x +2) =0 or (4x-√3) =0
⇒x = -2/√3 or √3/4

Answer 2

Answer: Zeros of the given equation $4\sqrt{3x^{2} } + 5x-2\sqrt{3}=0$ is $x=-\frac{2}{\sqrt{3} } or \frac{\sqrt{3} }{4}$.

Step-by-step explanation:

As given $4\sqrt{3x^{2} } + 5x-2\sqrt{3}$

As the given equation can be written as

$4\sqrt{3x^{2} }+5x -2\sqrt{3}=0\\4\sqrt{3x^{2} } +8x-3x-2\sqrt{3} =0\\4x(\sqrt{3x}+2 )-\sqrt{3} (\sqrt{3x}+2 =0\\\sqrt{3x}+2=0 or (4x-\sqrt{3} =0\\x=-\frac{2}{\sqrt{3} } or \frac{\sqrt{3} }{4}$

Hence, the correct answer is $-\frac{2}{\sqrt{3} } or \frac{\sqrt{3} }{4}$.

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