Question

Find zeros of 4x^2 - 1 and verify

Answer 1

4x²-1=0

(2x)²-1²=0

(2x+1)(2x-1)=0

2x+1=0

2x=-1

x= -1/2

or

2x-1=0

2x=1

x=1/2

sum of zeroes= -b/a

-1/2+1/2 = -(0)/4

(-1+1)/2 =0

0/2 =0

0 =0

L.H.S = R.H.S

product of zeroes= c/a

-1/2 × 1/2 = -1/4

-1/4 = -1/4

L.H.S =R.H.S