find zeros of 6x²+5x-6
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Let f(x)= 6x²+5x-6
For zeroes, f(x)=0.
6x²+5x-6=0
6x²+9x-4x-6=0
3x(2x+3)-2(2x+3)=0
(2x+3)(3x-2)=0
x= -3/2 or 2/3
Zeroes= -3/2 or 2/3
kalyaniprasad8:
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6x^2+5x-6=0
6x^2+9x-4x-6=0
3x(2x+3)-2(2x+3)=0
(2x+3)[3x-2]=0
so x=-3/2 ,2/3
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