Question

find zeros of 8x²+10x-7​

Answer 1

Answer:

x=1/2 & x=-7/4

Step-by-step explanation:

8x²+10x-7

8x²+14x-4x-7

8x²-4x+14x-7

4x(2x-1)+7(2x-1)

(2x-1)(4x+7)=0

x=1/2 & x= -7/4. (Ans.)

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Answer 2

Given:

• P(x)=8x²+10x-7

To Find:

• Zeroes

Solution:

$P(x)=8x²+10x-7 \\ 0 = 8x²+10x-7 \\ 0 = 8 {x}^{2} + 14x - 4x - 7 \\ 0 = 2x(4x + 7) - 1(4x + 7) \\ 0 = (4x + 7)(2x - 1)$

therefore zeroes are

$4x + 7 = 0 \\ 4x = - 7 \\ \boxed{x = \frac{ - 7}{4} }$

OR

$2x - 1 = 0 \\ 2x = 1 \\ \boxed{x = \frac{1}{2} }$

zeroes are (-7)/4 or ½ .

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