Find zeros of equation a/x-b + b/x-a = 2
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a(x-a) +b(x-b) /(x-b) (x-a) =2
=>(ax-a2+bx-b2)/(x2-bx-ax+ab)=2
=>ax-a2+bx-b2=2x2-2bx-2ax+2ab
=>ax+2ax+bx+2bx-a2-b2-2x2-2ab=0
=>3ax+3bx-a2-b2-2x2-2ab=0
=>a2+b2+2x2+2ab-3ax-3bx=0
=>a2+b2+2(x2+ab)-3x(a+b)=0
I think this will help you......
=>(ax-a2+bx-b2)/(x2-bx-ax+ab)=2
=>ax-a2+bx-b2=2x2-2bx-2ax+2ab
=>ax+2ax+bx+2bx-a2-b2-2x2-2ab=0
=>3ax+3bx-a2-b2-2x2-2ab=0
=>a2+b2+2x2+2ab-3ax-3bx=0
=>a2+b2+2(x2+ab)-3x(a+b)=0
I think this will help you......
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