Question

find zeros of of the polynomial p(x)= a^2x^2​

Answer 1

the correct answer is option number 3

Answer 2

Step-by-step explanation:

$\rm \: p(x)= a^2x^2$

$\rm \: To \: find \: zero \: of \: polynomial \: p(x)=0$

$\rm \: p(x)= a^2x^2$

$\rm p(x)=0$

$\rm \implies a^2x^2 = 0$

$\rm \implies (ax)(ax) = 0$

$\rm \implies \: x = - a \: \: or \: x = - a$

$\rm \implies \: x = - a, - a$

Answer 3

Step-by-step explanation:

$\rm \: p(x)= a^2x^2$

$\rm \: To \: find \: zero \: of \: polynomial \: p(x)=0$

$\rm \: p(x)= a^2x^2$

$\rm p(x)=0$

$\rm \implies a^2x^2 = 0$

$\rm \implies (ax)(ax) = 0$

$\rm \implies \: x = - a \: \: or \: x = - a$

$\rm \implies \: x = - a, - a$

Answer 4

Step-by-step explanation:

$\rm \: p(x)= a^2x^2$

$\rm \: To \: find \: zero \: of \: polynomial \: p(x)=0$

$\rm \: p(x)= a^2x^2$

$\rm p(x)=0$

$\rm \implies a^2x^2 = 0$

$\rm \implies (ax)(ax) = 0$

$\rm \implies \: x = - a \: \: or \: x = - a$

$\rm \implies \: x = - a, - a$

Answer 5

Step-by-step explanation:

$\rm \: p(x)= a^2x^2$

$\rm \: To \: find \: zero \: of \: polynomial \: p(x)=0$

$\rm \: p(x)= a^2x^2$

$\rm p(x)=0$

$\rm \implies a^2x^2 = 0$

$\rm \implies (ax)(ax) = 0$

$\rm \implies \: x = - a \: \: or \: x = - a$

$\rm \implies \: x = - a, - a$

Answer 6

Step-by-step explanation:

$\rm \: p(x)= a^2x^2$

$\rm \: To \: find \: zero \: of \: polynomial \: p(x)=0$

$\rm \: p(x)= a^2x^2$

$\rm p(x)=0$

$\rm \implies a^2x^2 = 0$

$\rm \implies (ax)(ax) = 0$

$\rm \implies \: x = - a \: \: or \: x = - a$

$\rm \implies \: x = - a, - a$

Answer 7

Step-by-step explanation:

$\rm \: p(x)= a^2x^2$

$\rm \: To \: find \: zero \: of \: polynomial \: p(x)=0$

$\rm \: p(x)= a^2x^2$

$\rm p(x)=0$

$\rm \implies a^2x^2 = 0$

$\rm \implies (ax)(ax) = 0$

$\rm \implies \: x = - a \: \: or \: x = - a$

$\rm \implies \: x = - a, - a$