Question

find zeros of P(x) = 3x^2-11x +8​

Answer 1

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Answer 2

by factorisation method,

3x^2-11x+8

product of roots=24

$um of roots = -11

3x^2-8x-3x+8

3x^2-3x-8x+8

3x(x-1)-8(x-1)

(3x-8)(x-1)

3x-8=0

3x=0+8 x-1=0

3x=8 x=0+1

x=8/3 x=1

therefore,the zeroes are 8/3 and 1