Question

find zeros of p(x)=7x(x-2)(3x+1)

Answer 1

Answer:

p(x)=7x(x-2)(3x+1)=0

thus ,it can possible that

either 7x=0 or x-2=0 or 3x+1=0

therefore

x= 0,2,-1/3

these are the zeros of p(x)

hope this will help you