Question

find zeros of p(x)=x4-16?

Answer 1

ⓗⓔⓨ ⓕⓡⓘⓔⓝⓓ

ⓗⓔⓡⓔ ⓘⓢ ⓨⓞⓤⓡ

ⓐⓝⓢⓦⓔⓡ


⊙
$x {}^{4} - 16 = 0$



$x {}^{4} = 16$


$x = 2$


Hope it helps you

Answer 2

Hey mate here is your answer :

x⁴ - 16

= (x² + 4) (x² - 4)

= (x² + 4) ( x + 2) ( x - 2)

Therefore x² = 4

Then x = +/- 2

The zeroes are +2 and - 2

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