Question

find zeros of polynomial​

Answer 1

Answer:

x^2+3x+2=0

x^2+2x+x+2=0

x(x+2)+1(x+2)=0

(x+1)(x+2)=0

x=-1 or x=-2

Answer 2

Hi there !

${x}^{2} + 3x + 2 \\ \\ = {x}^{2} + 2x + x + 2 \\ \\ = x(x + 2) + 1(x + 2) \\ \\ = (x + 2)(x + 1) \\ \\ x = - 2 \: and \: - 1$

By product rule,

x+2=0 and x+1=0

x= -1 and -2

Thankyou :)