find zeros of polynomial 4x^2-9
Answers
Answered by
39
The answer is given below :
Now,
4x^2 - 9
= (2x)^2 - 3^2
= (2x + 3)(2x - 3)
So, the zeroes of the given polynomial are
-3/2 and 3/2.
Identify Rule :
a^2 - b^2
= (a + b)(a - b).
Thank you for your question.
Now,
4x^2 - 9
= (2x)^2 - 3^2
= (2x + 3)(2x - 3)
So, the zeroes of the given polynomial are
-3/2 and 3/2.
Identify Rule :
a^2 - b^2
= (a + b)(a - b).
Thank you for your question.
Answered by
11
HEY!!
_________________________
✔To find zeros of 4 x 2 - 9 we equate it to zero and get
✔4 x 2 - 9 = 0
✔4 x 2 = 9
✔x 2 = 94
✔x = ± root 9/4 = ±3/2
Therefore,
▶▶Zeroes : x = 3/2 and - 3/2
_________________________
✔To find zeros of 4 x 2 - 9 we equate it to zero and get
✔4 x 2 - 9 = 0
✔4 x 2 = 9
✔x 2 = 94
✔x = ± root 9/4 = ±3/2
Therefore,
▶▶Zeroes : x = 3/2 and - 3/2
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