Question

Find zeros of polynomial p(x)=x^2+3x
pl reply fast it’s an urgent

Answer 1

Answer:

${x}^{2} + 3x = 0$

${x}^{2} = 0 - 3x$

${x}^{2} = - 3x$

$\frac{ {x}^{2} }{3} = - 3$

$\boxed{x = - 3}$

Answer 2

Answer:

x2+3x=0

x2= -3x

x=-3x/x

x and x gets cancelled, so we get:

x= -3, -3

I hope you get it.

Please mark the brainliest.