Find zeros of polynomial p(x)=x³-9x
Answers
Answered by
0
Answer:
x = 0, 3, -3
Step-by-step explanation:
x³ - 9x = 0
x(x²-9) = 0
So,
x = 0 and x² = 9
Therefore,
x = 0 and x = ± 3
Answered by
0
Answer:
p(x)=x³-9x
p(0)=0³-9(0)
=0-9(0)=
-9(0)=0
0=0/9
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